Aug 07, 17In general P ( x) being true for all x is different than for all x, if P ( x) is true, then such and such The former condition is false when ∃ x P ( x) is false But in this case, there may be other x such that P (x) is true So in ii), the conditional is true because your if part is false// increment p So in example 1 you assign to x after p is incremented In example 2 you assign to x before p is incremented Both examples has undefined behaviour, eg due to *p in the print statement where p is09 2 01 2 = 6 ×
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Apex